Question

If three balls are randomly drawn (without replacement) from a bowl containing 5 white and 6 black balls. What is the probability that one of the balls is white and the other two are black?

Answer 1

The probability of selecting one white ball and two black balls is 2/11.

Step-by-step explanation:

To find the probability that one of the balls is white and the other two are black, we need to consider the number of ways this can happen and divide it by the total number of possible outcomes.

There are 5 white balls and 6 black balls in the bowl, so the total number of balls is 11. If we select one white ball and two black balls, there are:

• 5 ways to choose one white ball (out of the 5 white balls)
• 6 ways to choose two black balls (out of the 6 black balls)

Therefore, the total number of ways to select one white ball and two black balls is 5 * 6 = 30.

The total number of ways to select any three balls from the 11 balls is 11C3 = 165.

So, the probability of selecting one white ball and two black balls is 30/165 = 2/11.