Question

can't run more than 22 times per month. Radio ads cost $540 each and can't run more than 34 times per month at this price. Each newspaper ad reaches 5450 potential customers, and each radio ad reaches 6250 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements. Maximize P=

Answer 1

To maximize the number of ad exposures to potential customers, use the constraints provided and solve it as a linear programming problem.

Step-by-step explanation:

To maximize the number of ad exposures to potential customers, we can use the following constraints:

n ≤ 22 (since we can't run more than 22 newspaper ads per month)

r ≤ 34 (since we can't run more than 34 radio ads per month at the given price)

The objective function to maximize is:

P = 5450n + 6250r

By combining the constraints and the objective function, we can solve this as a linear programming problem.