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What rate of interest compounded annually is required to double an investment in 3 years?

a. 0. 25992
b. $25. 992
c. 25. 992%
d. 22. 599%
e. none of the options display the corr

User Sudoremo
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1 Answer

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Final answer:

To double an investment in 3 years, the interest rate compounded annually required is approximately 0.25992, or 25.992%.

Step-by-step explanation:

To double an investment in 3 years, we need to determine the interest rate compounded annually. Let's assume the initial investment is $1. We can use the compound interest formula:

A = P(1 + r)^t

Where:

  • A is the final amount (which is 2 times the initial investment)
  • P is the principal amount
  • r is the interest rate as a decimal
  • t is the number of years

Plugging in the given values, we have:

2 = 1(1 + r)^3

(1 + r)^3 = 2

Now we need to solve for r. Taking the cube root of both sides, we get:

1 + r = ∛∛2

r = ∛∛2 - 1

This value is approximately 0.25992, or 25.992% (option a).

User Albi
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