Final answer:
Using the quadratic formula with given values a = 1, b = 1.2 × 10^-3, and c = -6.0 × 10^-3, we derive two potential solutions for x. The valid one being x = 0.0216 as negative concentrations are not possible in real-life contexts.
Step-by-step explanation:
To solve for x in a quadratic equation, we can use the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a). In this case, given the quadratic equation x² + 0.00088x - 0.000484 = 0, we have a = 1, b = 1.2 × 10-3, and c = -6.0 × 10-3. Upon applying the quadratic formula, we get two potential solutions for x: x = 0.0216 or x = -0.0224. However, in the context of a real-life situation such as concentration levels, a negative result isn't feasible, thus x = 0.0216 is the valid solution. This is consistent with the approach to evaluate both positive and negative results and disregard the non-sensical one.