Final answer:
To calculate the total area of solar collectors needed to replace a 750 MW power plant with a 2.00% efficiency rate, divide the total power output required (750,000 kW) by the power per square meter reaching the surface (1.30 kW/m²) and divide again by the efficiency rate.
Step-by-step explanation:
Photovoltaic Efficiency and Energy Requirements
When calculating the power per square meter from the sun at Earth's atmosphere, you use the total output of the sun and divide it by the surface area over which this power is spread. For example, the power output of the Sun is given as 4.00 × 1026 W. Since the Earth is located at a certain distance from the Sun, the power per square meter is obtained by dividing this power by the surface area of a sphere with a radius equal to the average distance from the Earth to the Sun (approximately 1 AU).
However, the question we're concerned with involves the installed photovoltaic (PV) systems on Earth's surface. These systems convert sunlight into electricity with a certain efficiency rate. For example, we assume a hypothetical situation where solar collectors replace an electric power plant that generates 750 MW of power. If those collectors have an average conversion efficiency of 2.00% of the maximum power that reaches Earth's surface, assumed to be 1.30 kW/m², we need to calculate the required area of solar collectors.
Let's take the total power needed from the solar collectors to be 750 MW, which is 750,000 kW. We divide this by 1.30 kW/m² to find the total area needed without considering efficiency, then further divide by the efficiency rate (2.00%) to find the actual required area. This results in a substantial area needed for solar panels to meet this power generation requirement. To find the area in km², we convert m² to km² by dividing by 106 (since 1 km² equals 106 m²).