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Now answer the following question: ∫ (x−2y² )dy C is the arc of the parabola y=x² from (−2,4) to (1,1) In the lecture, the minimum value of x is and minimum value of y is . The maximum value of x is and the maximum value of y is The line integral is Find the area enclosed by x=2cost+cos2t,y=2sint−sin2t,0≤t≤2π

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Final answer:

The question involves evaluating a line integral over a parabolic path and finding the area enclosed by a parametric curve using integration.

Step-by-step explanation:

The student is asking about evaluating a line integral of a function over a specified path, which in this case is the arc of a parabola. The problem involves using parameterization to express one variable in terms of another along a given curve, which simplifies the integral to a function of a single variable, thus making the integration more straightforward. For instance, along the parabolic path, one might solve for x in terms of y, or vice versa, to obtain an expression that can be integrated using standard techniques. Additionally, the student is asked to find the area enclosed by a parametric curve, which can be approached by integrating the given parametric equations over the interval from 0 to .

To solve for the line integral, we would need to replace x and dy using the relationships derived from the parabolic equation, for example, y = x² and dy = 2x dx, and then integrate over the specified limits. The area enclosed by a curve defined by parametric equations can be found by integrating x dy - y dx over the given range of the parameter, which

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