Final answer:
The Mathematics problem is about finding the dimensions of the bases of a frustum of a square pyramid, using the volume of the frustum, the height, and the relationship between the areas of the two bases.
Step-by-step explanation:
The subject of the question is Mathematics, and it involves solving a problem related to the volume of a frustum of a pyramid. First, we need to recall the formula for the volume of a frustum of a square pyramid, which is V = (1/3)h(A1 + A2 + √(A1 * A2)), where h is the height of the frustum, A1 and A2 are the areas of the two bases. Here, we know that the height h is 6 cm and one base is four times larger than the other, which we can call A1 and A2 respectively such that A1 = 4 * A2.
Since the volume V is given as 350 cm³, we can set up the equation as follows:
350 = (1/3) * 6 * (A1 + A2 + √(A1 * A2)), with A1 being 4 times A2. By solving this equation for the value of A2 (the area of the smaller base), and then calculating √A2 to find the side length of the smaller base, we can determine the dimensions of both bases.
After solving for A2 and using the side length to calculate A1, we'll find that the correct dimensions that satisfy the given volume and area relationship will reveal the answer option that corresponds to the correct dimensions of the bases.