Question

How many grams of NaC2H3O2 would be required to prepare 475 g of an aqueous solution containing 3.47% by mass NaC2H3O2?

(a) 16.51 g
(b) 14.53 g
(c) 16.39 g
(d) 13.41 g

Answer 1

To prepare the solution, approximately 0.57 g of NaC2H3O2 would be required.

Step-by-step explanation:

To calculate the amount of NaC2H3O2 needed to prepare the solution, you can use the formula:

grams of solute = (mass of solution) x (percent by mass)

First, convert the mass of the solution to grams: 475 g x 0.0347 = 16.5165 g. Then, multiply the mass of the solution by the percent by mass of NaC2H3O2: 16.5165 g x 0.0347 = 0.5725 g. Therefore, approximately 0.57 g of NaC2H3O2 would be required to prepare the solution.