Question

Solve 10x2+29x+21=0 by using the quadratic formula. Express your answers as reduced fractions. Show your steps. x=2a−b±b2−4acu=10b=29c=21x=2(10)−29±(29)2−4(10)(21)x=20−29±841−840 x=−29±

Answer 1

To solve the equation 10x²+29x+21=0 using the quadratic formula, first identify the values of a, b, and c as 10, 29, and 21 respectively. Then plug these values into the quadratic formula and simplify to find the solutions as x = -7/5 and x = -3/2.

Step-by-step explanation:

To solve the equation 10x²+29x+21=0 using the quadratic formula, let's first identify the values of a, b, and c. In this case, a = 10, b = 29, and c = 21. The quadratic formula is given by:

x = (-b ± √(b²-4ac))/(2a)

Plugging in the values:

x = (-29 ± √(29²-4(10)(21)))/(2(10))

Simplifying:

x = (-29 ± √(841-840))/(20)

Performing the calculations further:

x = (-29 ± √1)/(20)

x = (-29 ± 1)/(20)

Therefore, the solutions are:

x = (-29 + 1)/(20) = -28/20 = -7/5

x = (-29 - 1)/(20) = -30/20 = -3/2