Final answer:
The Expand, Guess, and Verify method leads to a closed form solution for the recurrence relation T(n) = 3T(n-1) with T(1) = 3, which is T(n) = 3^n.
Step-by-step explanation:
The question is asking for a closed form solution for the recurrence relation T(n) = 3T(n-1), with the base case T(1) = 3 using the Expand, Guess, and Verify method. We begin by expanding the recurrence:
- T(n) = 3T(n-1)
- T(n-1) = 3T(n-2)
- T(n-2) = 3T(n-3)
- ...
- T(2) = 3T(1)
Now, we substitute back into our original equation iteratively:
- T(n) = 3(3T(n-2))
- T(n) = 3^2T(n-2)
- T(n) = 3^2(3T(n-3))
- T(n) = 3^3T(n-3)
- ...
- T(n) = 3^(n-1)T(1)
Using our base case, T(1) = 3, we can then guess that T(n) = 3^n. To verify this, we can see that it holds for the base case, and assuming T(k) = 3^k, then T(k+1) = 3T(k) = 3(3^k) = 3^(k+1), which maintains the pattern. Therefore, the closed form solution is T(n) = 3^n.