Final answer:
To find the number of units that gives maximum profit, we need to determine the production level that maximizes the difference between revenue and cost. The maximum profit is achieved at 10 units.
Step-by-step explanation:
To find the number of units that gives maximum profit, we need to determine the production level that maximizes the difference between revenue and cost. In this case, revenue is given by the selling price of the product multiplied by the number of units produced. Cost is given by the fixed costs plus the variable costs per unit. So we have:
R = 2100x, where R is revenue
C = 42000/x + 200 + x, where C is cost
To find the maximum profit, we need to find the value of x that maximizes the difference between R and C. We can do this by taking the derivative of the profit function, setting it equal to zero, and solving for x.
Let P = R - C, where P is profit
Differentiate P with respect to x:
P' = 2100 - (42000/x^2 + 1)
Set P' equal to zero and solve for x:
2100 - (42000/x^2 + 1) = 0
42000/x^2 + 1 = 2100
42000/x^2 = 2099
x^2 = 42000/2099
x ~ 10.148
Since the number of units produced must be a whole number, the maximum profit is achieved at x = 10.
Therefore, the number of units that gives maximum profit is 10 units.