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Could the given matrix be the transition matrix of an absorbing Markov chain? [9.10.1.9001]⎣⎡.9.10.1.90001⎦⎤

User Kalombo
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Final answer:

The matrix values provided (9, 10, etc.) cannot represent an absorbing Markov chain because probabilities should be between 0 and 1. An absorbing Markov chain requires at least one absorbing state and that each row sums to 1, which is not the case here due to the incorrect values.

Step-by-step explanation:

The student has asked whether the given matrix could be the transition matrix of an absorbing Markov chain. An absorbing Markov chain is one with at least one absorbing state, which is a state that, once entered, cannot be left. For a matrix to represent an absorbing Markov chain, it must satisfy two conditions: The matrix must be square, and the sum of the values in each row must be 1, as rows represent the probabilities of transitioning from one state to another. Moreover, there should be at least one row with a probability of 1 leading to itself (indicating an absorbing state).

In the case of the given matrix, assuming it is a 2x2 matrix as it seems to be (despite the typo), we would need to see the matrix structured with appropriate probabilities. It should look something like:

  • The sum of each row equals 1.
  • There is at least one row with a diagonal entry of 1 and all other entries 0.

However, the given numbers cannot represent an absorbing Markov chain because the individual entries such as 9 and 9001 exceed 1, which is not possible in a probability matrix where all entries must be between 0 and 1, inclusive. The question might contain a typo, and the values are meant to be probabilities that sum up to 1, such as 0.9, 0.1, etc. Without the correct matrix, we cannot conclusively determine if it is a transition matrix for an absorbing Markov chain.

User AkshayBandivadekar
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