Question

What is the equation for the family of quartic functions with zeros ±2 and 1± √√3? a.y=k(x-2)(x+2)(x² − 2x − 2) b. y = k(x − 2)(x + 2)(x² + 2x − 2) | c. y = k(x − 2)(x+ 2)(x² − 3) d. = k(x − 2)(x + 2)(x². +3)

Answer 1

The equation for the family of quartic functions with specified zeros is y = k(x-2)(x+2)(x² − 2x − 2).

Step-by-step explanation:

The equation for the family of quartic functions with zeros ±2 and 1± √√3 is y = k(x - 2)(x + 2)(x² - 2x - 2) (option a).

This equation represents a quartic function because the highest power of x is 4. The zeros ±2 and 1± √√3 are obtained by setting each factor equal to zero and solving for x.

For example, setting (x - 2) equal to zero gives us x = 2, and setting (x + 2) equal to zero gives us x = -2.