Final answer:
To write numbers in polar form, we need to find their magnitude and angle. By applying the necessary formulas, we can find the polar form of the given complex numbers. For the numbers in (a), (b), and (c), the polar forms are 1*e^(i3(9-2π)), sqrt(117)*e^(-iπ/4*3), and 7*e^(i(8-i)) respectively. In (a), (b), and (c), the polar forms of 51, 7, and -0+6i are 51*e^(i0), 7*e^(i0), and 6*e^(i(π/2)).
Step-by-step explanation:
Given (a) (cos(9-2π) + i*sin(9-2π))^3, we can express the number in polar form as r*e^(iθ), where r is the magnitude of the number and θ is the angle it makes with the positive real axis. In this case, r = |cos(9-2π) + i*sin(9-2π)| = 1 and θ = 9-2π. Therefore, the polar form of (cos(9-2π) + i*sin(9-2π))^3 is 1*e^(i(9-2π)*3) = e^(i3(9-2π)).
In (b) (-3+i6+6i)^3, we can find the magnitude r = |-3+i6+6i| = sqrt((-3)^2+(6)^2+(6)^2) = sqrt(117) and the angle θ = arg(-3+i6+6i) = arctan((6+6)/(-3)) = -π/4. Therefore, the polar form of (-3+i6+6i)^3 is sqrt(117)*e^(-iπ/4*3).
In (c) 7e^(8+i)^4i, we can find the magnitude r = |7e^(8+i)^4i| = 7 and the angle θ = arg(7e^(8+i)^4i) = 8+i - 4i = 8-i. Therefore, the polar form of 7e^(8+i)^4i is 7*e^(i(8-i)).
In (a) 51, we can express the number in polar form by finding r = |51| = 51 and θ = arg(51) = 0. Therefore, the polar form of 51 is 51*e^(i(0)).
In (b) 7, we can express the number in polar form by finding r = |7| = 7 and θ = arg(7) = 0. Therefore, the polar form of 7 is 7*e^(i(0)).
In (c) -0+6i, we can express the number in polar form by finding r = |-0+6i| = 6 and θ = arg(-0+6i) = π/2. Therefore, the polar form of -0+6i is 6*e^(i(π/2)).