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Find tan²a, if: 5sin²a+13cos²a=6​

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Final answer:

To find tan²a, we need to use the trigonometric identities and the given equation. Start with the given equation: 5sin²a+13cos²a=6. Simplify and solve for cos²a. Then, use the identity tan²a=(1−cos²a)/cos²a to find tan²a.

Step-by-step explanation:

To find tan²a, we need to use the trigonometric identities and the given equation:

Start with the given equation: 5sin²a + 13cos²a = 6

Since sin²a = 1 - cos²a, we can substitute it in the equation:

5(1 - cos²a) + 13cos²a = 6

Simplify and solve for cos²a:

5 - 5cos²a + 13cos²a = 6

8cos²a - 5 = 6

8cos²a = 11

cos²a = 11/8

Now, we can use the identity tan²a = (1 - cos²a) / cos²a to find tan²a:

tan²a = (1 - 11/8) / 11/8

tan²a = (8 - 11) / 11

tan²a = -3/11

Therefore, tan²a = -3/11.

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