Question

What volume of the 17.5 M stock solution of acetic acid is required to prepare 500 mL of a 1.50 M acetic acid solution?

A) 15 mL
B) 20 mL
C) 25 mL
D) 30 mL

Answer 1

Approximately 42.86 mL of the 17.5 M stock solution of acetic acid is required to prepare 500 mL of a 1.50 M acetic acid solution.

Step-by-step explanation:

To determine the volume of the 17.5 M stock solution of acetic acid required to prepare 500 mL of a 1.50 M acetic acid solution, we can use the formula:

\(M_1V_1 = M_2V_2\)

Where:

• \(M_1\) = molarity of the stock solution
• \(V_1\) = volume of the stock solution
• \(M_2\) = desired molarity of the final solution
• \(V_2\) = desired volume of the final solution

Plugging the values into the formula:

\(17.5 imes V_1 = 1.50 imes 500\)

\(V_1 = \frac{1.50 imes 500}{17.5} = 42.86\) mL

Therefore, approximately 42.86 mL of the stock solution is required to prepare 500 mL of a 1.50 M acetic acid solution.