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What is the value of x in the system: −2.4x−3.6y=1.2

2.4x+1.2y=1.2

A. -1
B. 0
C. 1
D. -4.8

1 Answer

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Final answer:

To find the value of x in the system of equations -2.4x - 3.6y = 1.2 and 2.4x + 1.2y = 1.2, we can use the method of elimination. By multiplying the equations to eliminate x and solving, we find that x = -0.5.

Step-by-step explanation:

To find the value of x in the system of equations -2.4x - 3.6y = 1.2 and 2.4x + 1.2y = 1.2, we can use the method of elimination. We can multiply each equation by a suitable number to make the coefficients of x in both equations equal. In this case, we can multiply the first equation by -1 and the second equation by 1, which will eliminate x. Adding the two resulting equations gives:



-2.4x - 3.6y + 2.4x + 1.2y = 1.2 - 1.2



-2.4y = 0



Dividing both sides of the equation by -2.4, we find that y = 0.



Since y = 0, we can substitute this value into either of the original equations to solve for x. Substituting y = 0 into the first equation, we get:



-2.4x - 3.6(0) = 1.2



-2.4x = 1.2



Dividing both sides of the equation by -2.4, we find that x = -0.5.



Therefore, the value of x in the system of equations is -0.5.

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