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Find the value of k if x - 1 is a factor of p(x) in each of the following:

1. p(x) = kx^2 - √2x + 1
2. p(x) = kx^2 - 3x + k

1 Answer

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Final answer:

To find the value of k, substitute x = 1 into each polynomial and solve for k. For p(x) = kx^2 - √2x + 1, the value of k is √2 - 1. For p(x) = kx^2 - 3x + k, the value of k is 3/2.

Step-by-step explanation:

In order for x - 1 to be a factor of p(x), the expression p(x) must be divisible by x - 1. To find the value of k, we can use the Remainder Theorem. We substitute x = 1 into p(x) and set it equal to 0:

1. p(x) = kx^2 - √2x + 1

When x = 1:
p(1) = k(1)^2 - √2(1) + 1 = 0

Simplifying the equation, we have:

k - √2 + 1 = 0

Now, to find the value of k, we can isolate it by rearranging the equation:

k = √2 - 1

So, for p(x) = kx^2 - √2x + 1, the value of k is √2 - 1.

2. p(x) = kx^2 - 3x + k

When x = 1:
p(1) = k(1)^2 - 3(1) + k = 0

Simplifying the equation, we have:

k - 3 + k = 0

Combining like terms, we obtain:

2k - 3 = 0

Now, to find the value of k, we can isolate it by rearranging the equation:

k = 3/2

So, for p(x) = kx^2 - 3x + k, the value of k is 3/2.

User Ajay Gabani
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