166k views
3 votes
What is the range of the function f(x) = √(x-8) + 6 when f(x) > -8 ?

a) x > -2
b) x > -6
c) x > 6
d) x > 8

User Bwall
by
7.8k points

1 Answer

4 votes

Final answer:

The range of the function f(x) = √(x-8) + 6 when f(x) > -8 is x > 204.

Step-by-step explanation:

The range of a function represents the set of all possible output values. To find the range of the function f(x) = √(x-8) + 6 when f(x) > -8, we need to determine the set of values that satisfy this condition.

First, let's set up the inequality:

f(x) > -8

√(x-8) + 6 > -8

Next, we'll isolate the square root term:

√(x-8) > -14

Now we square both sides of the inequality:

x - 8 > 196

x > 204

Therefore, the range of the function f(x) = √(x-8) + 6 when f(x) > -8 is x > 204.

User Bazhikov
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories