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If you recorded the final volume of NaOH as 39.88 ml instead of 38.88 ml, what is the percentage error in the recorded volume?

a) 2.56%
b) 2.86%
c) 2.46%
d) 2.76%

1 Answer

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Final answer:

The percentage error in the recorded volume of NaOH is approximately 2.57%.

Step-by-step explanation:

To calculate the percentage error in the recorded volume, we can use the formula:

Percentage Error = |(Actual Value - Recorded Value)/Actual Value| x 100%

Given that the actual value is 38.88 ml and the recorded value is 39.88 ml, we can plug these values into the formula:

Percentage Error = |(38.88 - 39.88)/38.88| x 100%

Calculating this expression gives us:

Percentage Error = |(-1/38.88)| x 100% = 2.57%

Therefore, the percentage error in the recorded volume is approximately 2.57%. The correct option is a) 2.56%.

User TimeEmit
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