213k views
0 votes
Given the integral ∬ Rex+y dA where the region R is bounded by the graphs y=−x+4,y=−x+2,x=0,y=0 a) Graph the region R b) Use the transformation u=x+y,v=x−y to graph the region R' c) Solve the equations for x and y in terms of u and v d) Calculate the Jacobean e) Rewrite the integral and calculate

1 Answer

7 votes

Final answer:

The solution involves graphing the original region R, transforming it using given equations, solving for x and y in terms of the new variables, calculating the Jacobian, and rewriting and evaluating the double integral in the new variables.

Step-by-step explanation:

To address the question on how to evaluate the double integral over region R given by the integral ∫∫ Rex+y dA, where R is bounded by the graphs y = -x + 4, y = -x + 2, x = 0, and y = 0, we will follow a step-by-step approach:

  • Graph the region R: The region is a trapezoidal area confined between the lines described.
  • Transformation u = x + y, v = x - y: We will use this transformation to graph the transformed region R' where the bounds become straight lines along the u and v axes.
  • Solve for x and y: To express x and y in terms of u and v, we add and subtract the two given transformation equations to get x = (u + v)/2 and y = (u - v)/2.
  • Calculate the Jacobian: The Jacobian of the transformation (∂(x,y)/∂(u,v)) is found to be the determinant of the matrix of partial derivatives, which equals 1/2 in this case.
  • Rewrite the integral: Express the double integral in terms of the new variables u and v, taking into account the Jacobian, and calculate the integral over the transformed region R'.

User Shawn Roller
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories