Final answer:
The probability that a randomly selected person from an organization of 1000 likes either beer or wine is found using the principle of inclusion-exclusion, resulting in 900 people who like at least one of the two drinks. Dividing this by the total gives a probability of 0.9 or 90%, which is an option not listed in the provided multiple-choice answers.
Step-by-step explanation:
To find the probability that a randomly selected person from an organization of 1000 people likes either beer or wine, we can use the principle of inclusion-exclusion. According to the records, 800 like beer, 600 like wine, and 500 like both. We can find the total number of people who like at least one of the two drinks by adding those who like beer and those who like wine, and then subtracting those who like both (to avoid double-counting).
The calculation is as follows:
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- Number who like beer or wine = Number who like beer + Number who like wine - Number who like both
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- Number who like beer or wine = 800 + 600 - 500
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- Number who like beer or wine = 1400 - 500
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- Number who like beer or wine = 900
To find the probability, we divide this number by the total number of people in the organization:
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- Probability = Number who like beer or wine / Total number of people
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- Probability = 900 / 1000
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- Probability = 0.9 or 90%
Therefore, the probability that a randomly selected person has either of the two tastes is 0.9 or 90%, which is not one of the options provided in the question. It appears there might be a mistake in the options given.