95.2k views
4 votes
Find the kernel of the linear transformation.
T:R² →R² ,T(x,y)=(x+4y,y−x)

1 Answer

7 votes

Final answer:

The kernel of the linear transformation T:R² → R², where T(x, y) = (x + 4y, y - x), is the set containing only the zero vector, {(0,0)}, found by solving the system of equations created by setting the transformation equal to the zero vector.

Step-by-step explanation:

The question asks us to find the kernel of the linear transformation T:R² → R², where T(x, y) = (x + 4y, y - x). The kernel of a linear transformation consists of all vectors in the domain that map to the zero vector in the codomain. To find the kernel, we need to solve the equation T(x, y) = (0, 0). This results in a system of equations:

  • x + 4y = 0
  • y - x = 0

Solving this system of equations, we set the equations equal to zero:

  • x + 4y = 0 → x = -4y
  • y - x = 0 → y = x

Since y = x, substituting into the first equation gives x + 4(x) = 0, which simplifies to 5x = 0. So, x = 0 and consequently,

User Zudwa
by
7.7k points