76.4k views
3 votes
Sketch the region of integration and set up integrals for both orders of integration, then use the more convenient order to evaluate the integral over the plane region R

∬R ex² dA,R:0≤y≤18,x=y/3,≤x≤x=6.

User Mina Kolta
by
8.8k points

1 Answer

2 votes

Final answer:

The question involves sketching the region of integration for a given plane region R and setting up the integrals for both orders of integration, then evaluating the integral of ex² over R. The bounds form a trapezoidal shape, and the most convenient order might be to integrate with respect to x first due to the nature of the function ex².

Step-by-step explanation:

The student has been tasked with sketching the region of integration and setting up integrals for both orders of integration for the given plane region R, which is bounded by 0≤y≤18, x=y/3, and x=6. To sketch this region, we can note that the bounds form a trapezoidal shape with one vertical side (x=6), one slanted side following the line x=y/3, and the horizontal bounds being y=0 and y=18. The first order of integration would be with respect to y first (from x*3 to 18) and then with respect to x (from y/3 to 6). The second order of integration would be in x first (from y/3 to 6) and then in y (from 0 to 18).

Considering the integral ∫R ex² dA, the most convenient order of integration is often that which allows for simpler integration limits and potentially easier integration functions. Given the exponentiation of an x term, one might often choose to integrate with respect to x first. However, due to the nature of the exponential function and the fact that ex² does not have a simple antiderivative in terms of elementary functions, evaluating this integral directly may not be straightforward. In practice, this integral might require special functions or numerical methods for exact evaluation.

User NPKR
by
8.1k points