13.5k views
2 votes
Find the rate of formation of product C in m/s if the reaction 2A + B → 3C has a rate of 0.005 m/s..

a) 0.00166
b) 0.0025
c) 0.00333
d) 0.005

User Josh Adell
by
8.1k points

1 Answer

4 votes

Final answer:

The rate of formation of product C, based on the stoichiometry of the reaction 2A + B → 3C and given the reaction rate of A and B as 0.005 m/s, should be 0.0075 m/s. However, this does not match any of the provided answer options, indicating a possible error or misunderstanding in the question or options.

Step-by-step explanation:

To find the rate of formation of product C when the overall reaction rate is given, we must consider the stoichiometry of the reaction. The given reaction is 2A + B → 3C. If the rate of formation of A and B is 0.005 m/s, this rate refers to how quickly A and B are being consumed. Since for every 2 molecules of A, 3 molecules of C are produced, the rate of production of C can be found using a stoichiometric factor.

So, the rate of formation of C is (3/2) × rate of formation of A. Using the given reaction rate for A and B (0.005 m/s):

Rate of formation of C = (3/2) × 0.005 m/s = 0.0075 m/s

However, none of the options provided matches 0.0075 m/s. There seems to be a misunderstanding because based on the stoichiometry of the reaction, the rate of formation of product C should be higher than the rate of disappearance of reactants A and B.

User LexLythius
by
8.6k points