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Fe3+ + Cu+ ➼ Fe2+ + Cu2+

A. Fe3+ is oxidized
B. Cu+ is the reducing agent
C. The oxidation number of Cu+ decreased
D. The total number of electrons increased.

User TMann
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1 Answer

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Final answer:

Fe3+ is oxidized and Cu+ is the reducing agent in this redox reaction. The oxidation number of Cu+ increases, and the total number of electrons increases.

Step-by-step explanation:

In this redox reaction, Fe3+ is oxidized because its oxidation number increases from +3 to +2. On the other hand, Cu+ is the reducing agent because it is being oxidized, as its oxidation number increases from +1 to +2. The oxidation number of Cu+ does not decrease. Instead, it increases.

The total number of electrons in the reaction increases because Fe3+ gains one electron to become Fe2+, while Cu+ loses one electron to become Cu2+.