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Find dy/dx using logarithmic differentiation.

y = (3 + x)^4/x , x>0

Find dy/dx using logarithmic differentiation. y = (3 + x)^4/x , x>0-example-1

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I think that’s ur answer sorry if it’s wrong
Find dy/dx using logarithmic differentiation. y = (3 + x)^4/x , x>0-example-1
User Aprilmintacpineda
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