Final answer:
The correct application of the quadratic formula for the equation y = 3x² - 4x + 11 is 4/3 - 4(3 × 11).
Step-by-step explanation:
The quadratic equation y = 3x² - 4x + 11 can be solved using the quadratic formula, which is:
x = (-b ± √(b² - 4ac)) / (2a)
For this equation, a = 3, b = -4, and c = 11. Substituting these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)² - 4(3)(11))) / (2(3))
x = (4 ± √(16 - 132)) / 6
x = (4 ± √(-116)) / 6
The expression inside the square root (√(-116)) is negative, which means that the equation has no real solutions. Therefore, the correct application of the quadratic formula for this equation is option d) 4/3 - 4(3 × 11).