Question

For the function f(x) = x³ - 2x² -11x +12, find f(0), f(1) and f(2).

Answer 1

For the cubic function f(x) = x³ - 2x² -11x +12, the values for the function at the points x=0, x=1, and x=2 are f(0) = 12, f(1) = 0, and f(2) = -10 respectively.

Step-by-step explanation:

To find the values of f(x) for given inputs, we substitute these values into the function f(x) = x³ - 2x² -11x +12 and calculate the result.

For f(0), we substitute x with 0:

• f(0) = (0)³ - 2*(0)² - 11*(0) + 12 = 12

For f(1), substitute x with 1:

• f(1) = (1)³ - 2*(1)² - 11*(1) + 12 = 1 - 2 - 11 + 12 = 0

For f(2), substitute x with 2:

• f(2) = (2)³ - 2*(2)² - 11*(2) + 12 = 8 - 8 - 22 + 12 = -10

Therefore, the values are f(0) = 12, f(1) = 0, and f(2) = -10.