Final answer:
The molarity of the glucose solution is 0.216 M.
Step-by-step explanation:
The molarity (M) of a glucose solution can be calculated by dividing the moles of glucose by the volume of the solution in liters. In this case, the solution is 10% glucose (W/W), meaning that 10 grams of glucose are present in 100 grams of the solution.
To find the moles of glucose, we divide the mass of glucose by its molar mass (180 g/mol).
Mass of glucose = 10 grams * (180 g/mol)/(100 grams) = 18 g/mol
Next, we need to find the volume of the solution in liters. The density of the solution is given as 1.20 g/mL, so 100 grams of the solution will occupy a volume of 100 grams / 1.20 g/mL = 83.33 mL = 0.08333 L.
Finally, we can calculate the molarity:
Molarity = Moles of glucose / Volume of solution = 18 g/mol / 0.08333 L = 0.216 M
Therefore, the molarity of the glucose solution is 0.216 M.