313 views
5 votes
State the general formula for xn+1, then + 1st iterate in Newton’s method to solve f(x) = 0.

User Sava
by
8.0k points

1 Answer

3 votes

Final answer:

The general formula for the next iterate in Newton's method is x_n+1 = x_n - f(x_n)/f'(x_n). To find the iterate, compute f'(x) and use the formula with an initial guess x_0. Applying this to the quadratic equation x^2 + 0.0211x - 0.0211 = 0, we can determine the first iterate starting from x_0.

Step-by-step explanation:

The general formula for the next iterate in Newton's method to solve f(x) = 0 is given by:

xn+1 = xn - f(xn)/f'(xn).

To find the first iterate, we need to calculate f'(x), the derivative of f(x), and then apply the formula using an initial guess x0 (often taken as x0 = 0 or a value close to an expected root). For instance, if we have a quadratic equation of the form ax2 + bx + c = 0, and we want to find the roots using Newton's method, we first need to differentiate the equation to find f'(x), which would be 2ax + b. Then we can apply the Newton's formula to iterate towards a solution.

Let's take the equation x2 + 0.0211x - 0.0211 = 0 as an example. The first derivative of this function f'(x) would be 2x + 0.0211. Applying the Newton's method formula and assuming our x0 is 0 (x-sub-zero or x-reaction), we can find the first iterate (x1) for this specific equation.

User Andrey Rubshtein
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories