Final answer:
The canonical form of the given PDE 6uₓ ₓ - 7uₓy + uyy = 0 is uyy - 7uₓy + 6uₓ ₓ = 0. To find a solution, we define new variables p = uₓ ₓ, q = uₓy, and r = uyy. Rearranging the equation, we get r - 7q + 6p = 0. By integrating this equation, we find u = 6vₓ + C₁(x) and v = 7vₓ + C₂(y), where C₁(x) and C₂(y) are arbitrary twice differentiable functions.
Step-by-step explanation:
The given partial differential equation is 6uₓ ₓ - 7uₓy + uyy = 0. To find the canonical form of this PDE, we start by arranging the terms in descending order of the highest derivative. So, the equation becomes uyy - 7uₓy + 6uₓ ₓ = 0.
Now, let's define new variables as follows: p = uₓ ₓ, q = uₓy, and r = uyy. Using these variables, the equation becomes:
r - 7q + 6p = 0
This is the canonical form of the given PDE. To find a solution in terms of two arbitrary twice differentiable functions, we can take p, q, and r as the derivatives of two functions with respect to appropriate variables. Let's say p = vₓ and q = vₓy, where v is a twice differentiable function. Now, integrating r - 7q + 6p = 0 with respect to x and y, we get:
u = 6vₓ + C₁(x) and v = 7vₓ + C₂(y)
Here, C₁(x) and C₂(y) are arbitrary twice differentiable functions.