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Find the equation for an exponential function that passes through the pair of points given below. (Round all coefficients to four decimal places when necessary.) PRACTICE AND cal + Ope Fur Х Syr : through (1, 1.6) and (2, 0.32) Rel f(x) = -1.6094x 림 8e1 x Set voo! Vec Need Help? Read It Watch It Trig Gre Submit Answer H

User Amoss
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Final answer:

To find the equation for an exponential function that passes through the points (1, 1.6) and (2, 0.32), we can use the general form of an exponential function, y = a * b^x. By substituting the values of the points into the equation and solving for the constants a and b, we find that the equation becomes y = 8 * 0.2^x.

Step-by-step explanation:

To find the equation for an exponential function that passes through the points (1, 1.6) and (2, 0.32), we can use the general form of an exponential function, which is y = a * b^x, where a and b are constants. We can substitute the x and y values of both points into the equation to create a system of two equations. Solving this system of equations will give us the values of a and b, which we can then use to write the equation for the exponential function.

Substituting the values of (1, 1.6) into the equation, we get: 1.6 = a * b^1

Substituting the values of (2, 0.32) into the equation, we get: 0.32 = a * b^2

By dividing the second equation by the first equation, we can eliminate the variable a and solve for b: 0.32/1.6 = b^2/b^1 = b

Therefore, b = 0.2. Substituting this value into the first equation, we can solve for a: 1.6 = a * 0.2^1. Simplifying, we get a = 8.

Therefore, the equation for the exponential function is y = 8 * 0.2^x.

User JClarke
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