Question

Using the function y=1+2x/x graph the derivative and antiderivative so that the maximum value of the antiderivative function is twice as great as the maximum value of the function Using the graph estimate the y intercept and the end value of the function as x approaches +infinity Then interpret the y intercept and the end behavior of the antiderivative function into the following

A phone company charges $2 for every minute of a long distance call with an initial charge of $1 to start the call. Using the function provided

Answer 1

To find the derivative of the function y = 1 + 2x/x, we can use the quotient rule. The derivative of y is given by y' = (2*x - (1 + 2x))/(x^2).

Step-by-step explanation:

To find the derivative of the function y = 1 + 2x/x, we can use the quotient rule. The quotient rule states that if we have a function of the form f(x) = g(x)/h(x), then f'(x) = (g'(x)h(x) - g(x)h'(x))/[h(x)]^2.

In this case, g(x) = 1 + 2x and h(x) = x. Taking the derivatives of g(x) and h(x), we have g'(x) = 2 and h'(x) = 1. Plugging these values into the quotient rule formula, we get y' = (2*x - (1 + 2x))/(x^2).

To graph this derivative, we can plot points on the graph using various values of x and y' and then connect the points with a curve. The graph will show the rate of change of the original function at different points.