Question

Vriting the fraction as the sum (or difference ) of fractic (6x^(5)-2x^(2)-2x^(3)-8)/(2x^(3))

Answer 1

To rewrite the fraction as a sum, divide every term in the numerator individually by the denominator. The result is 3x^2 - x^-1 - 1 - 4x^-3.

Step-by-step explanation:

The question asks to rewrite the fraction (6x5 - 2x2 - 2x3 - 8) / (2x3) as the sum or difference of its parts. This can be done by dividing each term in the numerator by the denominator.

Here's the step-by-step process: First, divide 6x5 by 2x3 to get 3x2. Next, divide -2x2 by 2x3 to get -x-1. Then, divide -2x3 by 2x3 to get -1. Finally, divide -8 by 2x3 to get -4x-3.

Therefore, the given fraction can be written as the sum: 3x2 - x-1 - 1 - 4x-3.