Final answer:
The minimum bandwidth required to transmit data at a rate of 300kbits/s using an 8-level PAM scheme that satisfies Nyquist's First Criterion is 50kHz.
Step-by-step explanation:
The student has asked about the minimum transmission bandwidth required to transmit data at a rate of 300kbits/s using a Pulse Amplitude Modulation (PAM) scheme with M=8 levels that satisfies Nyquist's First Criterion for zero Inter-symbol Interference (ISI). The Nyquist Criterion states that the minimum bandwidth required to transmit an M-level PAM signal without ISI is given by (1/2) x (baud rate), where the baud rate is the number of signal changes or symbols per second. Since we have an 8-level PAM, each symbol encodes ℓlog2M bits. Hence, for M=8 levels, each symbol encodes 3 bits. The data rate is 300kbits/s, so the symbol rate is 300kbits/s divided by 3 bits/symbol, which equals 100ksymbols/s. Thus, the minimum bandwidth required is (1/2) x 100ksymbols/s = 50kHz