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The balanced equation for octane combustion is given. Calculate the mass of CO2 produced if 5.0 X 10 2 g of octane is available.

2C8H18 (l) + 25 O2 (g) → 16 CO2 (g) + 18 H2O (g)

User Purag
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Final answer:

The mass of CO2 produced is 1540 g.

To calculate the mass of CO2 produced when 5.0 X 10^2 g of octane is available, you need to convert the mass of octane to moles and then use the balanced equation to find the moles of CO2 produced. Finally, you can calculate the mass of CO2 by multiplying the moles of CO2 by its molar mass.

Step-by-step explanation:

To calculate the mass of CO2 produced when 5.0 X 102 g of octane is available, we first need to convert the mass of octane to moles.

The molar mass of octane (C8H18) is 114.22 g/mol.

Therefore, there are (5.0 X 102 g) / (114.22 g/mol) = 4.37 mol of octane.

From the balanced equation, we can see that for every 2 moles of octane, 16 moles of CO2 are produced.

So, for 4.37 mol of octane, we will have (4.37 mol) / 2 * 16 = 35.0 mol of CO2.

Finally, we can calculate the mass of CO2 by multiplying the moles of CO2 by its molar mass.

The molar mass of CO2 is 44.01 g/mol.

Therefore, the mass of CO2 produced is (35.0 mol) * (44.01 g/mol) = 1540 g.

User Tiwana
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