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A rumour spreads exponentially through a school. When school begins (at 9 a.m.) 18 people know it. By

10 a.m. 42 people know it.
Let N be the number of people who know the rumour after t minutes.
a Find constants A and k so that N = Ae^kt
b How many people know the rumour at 10:30?
c There are 1200 people in the school. According to the exponential model at what time will everyone
know the rumour?

User Jachguate
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1 Answer

5 votes

Constants A and K are

A = 18 and K = 0.014

At 10:30 am 63 people know the rumour

The rumour should have gone round the school by 2 pm

How to find the constants

From the problem we can deduce that

The starting value A = 18

To find the number of people who know the rumor at 10:30 we solve as follows

we solve for K, using the given values

42 = 18e^(60k) from 9 am to 10 am = 60 minutes

e^(60k) = 42/18

take In of both sides

60k = In(42/18)

k = 0.014

From 9 am to 10:30 am is 90 minutes

N = 18e^(90 * 0.014)

N = 63.46 = 63

To find the time when everyone in the school (1200 people) knows the rumour

1200 = 18e^(0.014 * t)

e^(0.014 * t) = 1200/18

take In of both sides

0.014t = In(1200/18)

t = 299.98 approximately 300 minutes

300/60 = 5 hours

9 am + 5 hours = 2 pm

User Maurizio Benedetti
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8.2k points