Question

A random sample of 24 wolf litters in Ontario, Canada, gave an average of x1 = 4.4 wolf pups per litter, with estimated sample standard deviation s1 = 1.0. Another random sample of 11 wolf litters in Finland gave an average of x2 = 2.8 wolf pups per litter, with sample standard deviation s2 = 1.3.

(a) Categorize the problem below according to parameter being estimated, proportion p, mean μ, difference of means μ1 – μ2, or difference of proportions p1 – p2. Then solve the problem.

Answer 1

The problem is about the difference of means between two samples of wolf litters. A two-sample t-test would be used for the analysis. The samples' means and standard deviations have been provided for solving the problem.

Step-by-step explanation:

The problem given involves comparing the means of two independent samples (wolf litters in Ontario and Finland). Therefore, the parameter being estimated is the difference of means μ1 – μ2. We are given two sample means, x1 and x2, and two sample standard deviations, s1 and s2. To solve this problem, we would typically use a two-sample t-test to determine if there is a significant difference between the two population means.

The random variable X in example 98 is the weight of a single bag of candies. When conducting a hypothesis test about the vaccination rate in the provided study, the appropriate distribution would be the normal distribution if the Central Limit Theorem applies, because we are dealing with a sample proportion, and the population standard deviation is known. With regards to the study questions with p-values of 0.07 and 0.006, in a study with an α level of 0.05, a p-value of 0.07 would not be significant, and we would fail to reject the null hypothesis. However, with an α level of 0.01 and a p-value of 0.006, we would reject the null hypothesis, indicating a statistically significant result.