Final answer:
The molarity of 0.127 mol of sucrose in 700 ml of solution is 0.1814 M; you find this by converting milliliters to liters and then dividing moles of solute by liters of solution.
Step-by-step explanation:
The molarity of a solution is determined by the number of moles of solute divided by the volume of the solution in liters. To find the molarity of 0.127 mol of sucrose in 700 ml of solution, you first convert the volume from milliliters to liters. Since 1 L = 1000 ml, 700 ml is equal to 0.7 liters. Then you use the molarity formula:
Molarity (M) = moles of solute / liters of solution
Molarity of sucrose = 0.127 mol / 0.7 L = 0.1814 M
So, the molarity of sucrose in the solution is 0.1814 M.
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, we have 0.127 moles of sucrose and a solution volume of 700 mL, which is equivalent to 0.7 L.
To calculate the molarity, we divide the moles of sucrose by the volume of the solution: 0.127 mol / 0.7 L = 0.181 M.
Therefore, the molarity of 0.127 mol of sucrose in 700 mL of solution is 0.181 M.