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In the local schnuck's parking lot that had 200 cars, 50 cars are white, 30 cards are red, and 20 cars are silver. one car will be selected at random from the parking lot. if each car in the parking lot has only one color, which of the following cannot be the probability that the selected car will be green?

User DaemonFire
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Final answer:

The probability of selecting a green car from the lot cannot exceed the proportion of green cars to the total number of cars; any probability suggesting more than the remaining number of cars or over 100% is incorrect.

Step-by-step explanation:

In the scenario described where a parking lot contains 200 cars, with 50 white, 30 red, and 20 silver, the probability of selecting a car of any other color that is not mentioned corresponds to the remaining portion of cars.

Assuming that green cars are among the unspecified colors in the lot, the probability of selecting a green car would be based on the total number of green cars present in the lot out of 200. However, any probability presented above the available remaining cars' ratio or beyond the total composition of the parking lot (such as a probability suggesting more than the remaining number of cars or a probability suggesting a certainty higher than 100%) cannot be the correct probability for a green car being chosen.

To provide an example similar to the provided exercise, if a probability of 1/4 were suggested, there would need to be exactly 50 green cars in the lot for this to be accurate.

Given the numbers provided, this is impossible because 50 white, 30 red, and 20 silver cars already account for 100 of the 200 available spots. Thus, a probability such as 3/4 for selecting a green car is not possible because it would suggest that 150 out of 200 cars are green, which exceeds the number of unspecified cars. Only the remaining 100 cars could possibly be green (after excluding the mentioned white, red, and silver cars), so the probability of selecting a green car cannot exceed 1/2.

User Shahin Ali Agharia
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