Solve log2(3x) + log2 (4) = 4 a.) x=4/3 b.) x=3/4 c.) x=4 d.) x=6

asked Nov 17, 2022 33.5k views

4 votes

Solve log2(3x) + log2 (4) = 4

a.) x=4/3
b.) x=3/4
c.) x=4
d.) x=6

by Mira

3.6k points

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3 votes

Explanation:

log2(3x) + log2(4) = 4

log2(3x × 4) = 4

log2(12x) = 4

12x = 2⁴

12x = 16

x = 16/12

= 4/3

Jsstuball answered Nov 21, 2022

3.8k points

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