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A person kicks a soccer ball to score a goal. The mass of the soccer ball is 0.5 kg, and the mass of the foot-leg system is 2.2 kg. The soccer ball is initially at rest, and after the kick it travels at 33 m/s. The coefficient of restitution between the ball and the foot is 0.75.

1. How fast was the foot traveling when the person kicked the ball?

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Final answer:

To find the speed of the foot when the person kicked the ball, we can use the principle of conservation of momentum. The speed of the foot when the person kicked the ball is approximately 37.1 m/s.

Step-by-step explanation:

To find the speed of the foot when the person kicked the ball, we can use the principle of conservation of momentum. According to this principle, the total momentum before the kick is equal to the total momentum after the kick.

Since the soccer ball is initially at rest, its momentum before the kick is zero. The momentum of the foot-leg system before the kick can be calculated using the equation:

Pinitial = mfoot-leg * vinitial

where mfoot-leg is the mass of the foot-leg system and vinitial is the initial velocity of the foot.

After the kick, the soccer ball travels at 33 m/s. Using the coefficient of restitution and the principle of conservation of momentum, we can calculate the velocity of the foot after the kick as follows:

vfinal = (mfoot-leg * vinitial + msoccer ball * vsoccer ball) / (mfoot-leg + msoccer ball)

We can rearrange this equation to solve for vinitial:

vinitial = (vfinal * (mfoot-leg + msoccer ball) - msoccer ball * vsoccer ball) / mfoot-leg

Plugging in the given values, we have:

vinitial = (33 m/s * (2.2 kg + 0.5 kg) - 0.5 kg * 33 m/s) / 2.2 kg

Solving this equation gives the speed of the foot when the person kicked the ball to be approximately 37.1 m/s.

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