43.7k views
0 votes
Cookies are baked in an oven at a temperature of 325° . The cookies are removed and placed in a room with a constant temperature of 74° . After 7 minutes, the temperature of the cookies is 165° . From Newtons Law of Cooling, this situation can be modeled by the differential equation

T'=k(T−74), T(0)=325, and T(7) = 165.

where T=T(t)= the temperature of the cookies at time t (minutes).

(a) Solve the differential equation to determine the temperature of the cookies as a function of time. (This is a separable differential equation) T(t)=

1 Answer

1 vote

Final answer:

To solve the separable differential equation, we separate the variables and integrate both sides, apply initial conditions to solve for the integration constant and rate constant, and obtain the function T(t)=74+(251)e^(kt), which describes the temperature of the cookies as a function of time.

Step-by-step explanation:

The differential equation given is T'=k(T−74), with initial conditions T(0)=325 and T(7)=165. To solve this separable differential equation, we need to separate the variables and integrate both sides. The separation of variables gives us dT/(T-74) = k dt. By integrating both sides, we obtain ∫ dT/(T-74) = ∫ k dt which leads to ln|T-74| = kt + C, where C is the integration constant.

To solve for C, use T(0)=325: ln|325-74| = k(0) + C, thus C = ln|251|. To find k, use T(7)=165: ln|165-74| = k(7) + ln|251|, yielding k after calculations. The final result after solving for k and substituting it back is T(t) = 74 + (251)e^(kt), where e is the base of natural logarithms and k is the constant found from the conditions provided.

The exact value of k is found from this equation by plugging in the values for t at 7 minutes and the corresponding temperature, then solving for k algebraically. Once we have the value of k, we substitute it back into the equation for T(t) to get our final temperature function with respect to time.

User Xiaoyifang
by
7.6k points