Final answer:
The period of oscillation of a meter stick pendulum, suspended by a 0.33 m string, can be calculated using the simple pendulum formula and is approximately 1.155 seconds given the acceleration due to gravity of 9.8 m/s².
Step-by-step explanation:
Calculating the Period of a Pendulum
The question involves a meter stick acting as a pendulum and suspended by a string, requiring determination of its period of oscillation given the acceleration due to gravity (g) and the length of the string. To solve this, we use the formula for the period (T) of a simple pendulum:
T = 2π√(l/g),
where T is the period, l is the length, and g is the acceleration due to gravity. For the pendulum in question, the string length l is 0.33 meters, and the acceleration due to gravity g is 9.8 m/s². Substituting, we get:
T = 2π√(0.33/9.8)
Which we can calculate as:
T ≈ 2π√(0.03367) ≈ 2π(0.1835) ≈ 1.155 seconds.
The period of oscillation of the meter stick pendulum is therefore approximately 1.155 seconds.