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A forklift can raise a 336.67 kg crate from rest to a height of 8.4 m with a final upward velocity of 7.6 m/s. if it takes 3.15 s to accelerate the load to this upward velocity; what is the net upward force exerted on the load during the acceleration?

User ToxicFrog
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Final answer:

The net upward force exerted on the crate during acceleration is calculated using Newton's second law, resulting in a force of approximately 811.36 newtons. This does not include the force required to counteract gravity, which would be additional.

Step-by-step explanation:

The student asked to calculate the net upward force exerted on a 336.67 kg crate during its acceleration by a forklift. This problem requires the application of Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). To find the acceleration, we use the formula a = (v - u) / t, where 'v' is the final velocity, 'u' is the initial velocity (zero since the crate starts from rest), and 't' is the time taken to reach this final velocity. With the final velocity v = 7.6 m/s and time t = 3.15 s, the acceleration a = 7.6 m/s / 3.15 s = 2.41 m/s².

We then apply Newton's second law to find the net upward force: F_net = m × a = 336.67 kg × 2.41 m/s², which gives the net force F_net needed to accelerate the crate. After calculating, we find that the net force is approximately 811.36 newtons acting upwards.

It is important to note that this net force includes the force required to overcome the weight of the crate (gravitational force) as well as the force needed to accelerate it. Therefore, to find the total force exerted by the forklift, we would need to add the weight of the crate to the net force calculated. The weight (gravitational force) can be calculated using F_gravity = m × g, where 'g' is the acceleration due to gravity (9.81 m/s²).

User Hans Vn
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