Question

A cyclist is riding along a flat, straight, smooth bike path. the cyclist has a mass of 70.0 kg. their bike is made of carbon fiber and has a mass of 7.30 kg. they can accelerate from rest to approximately 1.70 m/s in about a minute. 80. after stopping, the cyclist resumes pedaling, accelerating at a rate of 0.300 m/s² . after 50.0 seconds, what is the displacement of the cyclist since stopping?

Answer 1

To calculate the displacement of the cyclist since stopping, we need to calculate the distance covered during the acceleration phase and the distance covered during the constant velocity phase.

Step-by-step explanation:

To calculate the displacement of the cyclist since stopping, we need to calculate the distance covered during the acceleration phase and the distance covered during the constant velocity phase.

During the acceleration phase, the cyclist accelerates at a rate of 0.300 m/s² for 50.0 seconds. Using the equation:

d = v₀t + 0.5at²

where d is the displacement, v₀ is the initial velocity, t is the time, and a is the acceleration, we can calculate the distance covered during the acceleration phase.

During the constant velocity phase, the cyclist travels at a constant velocity for the remaining time after the acceleration phase. Since the velocity is constant, the displacement during this phase is given by:

d = vt

where v is the constant velocity and t is the time.

By adding the displacements during the acceleration and constant velocity phases, we can find the total displacement of the cyclist since stopping.