Question

A certain transverse wave is described by

Y(x,t)= B cos [ 2π (x/L - t/T) ]
,
where B= 5.30mm , L = 29.0cm , and = 3.10x10² s.
Determine the wave's amplitude

Answer 1

The amplitude of the transverse wave described by the wave equation Y(x,t)= B cos [ 2π (x/L - t/T) ], where B= 5.30mm, is 5.30 mm.

Step-by-step explanation:

The question asks us to determine the amplitude of a certain transverse wave given by the wave equation Y(x,t)= B cos [ 2π (x/L - t/T) ]. The equation represents a wave with certain parameters including amplitude (B), wavelength (L), and period (T). The amplitude of the wave, which is the maximum extent of a vibration or oscillation measured from the position of equilibrium, can be directly read from the wave equation.

The amplitude is given as B = 5.30 mm. Since the amplitude is the absolute value of the maximum displacement from equilibrium, the units of millimeters (mm) indicate the amplitude of this wave is 5.30 mm.