Final answer:
The probability of selecting two moderate exercisers in succession from the group is approximately 0.009529 when rounded to six decimal places, which does not match any of the options given.
Step-by-step explanation:
The question asks us to find the probability that two randomly selected people from a group of 948 are both moderate exercisers. To answer this, we use the formula for the probability of two independent events: P(A and B) = P(A) × P(B). Here, the probability of selecting one moderate exerciser is the number of moderate exercisers divided by the total number of subjects, P(A) = 93/948.
The probability of selecting another moderate exerciser is slightly different, as there is one less moderate exerciser and one less total subject after the first pick, P(B) = 92/947.
Calculating this we get:
- P(A) = 93/948 = 0.0981043
- P(B after A) = 92/947 ≈ 0.0971505
- P(A and B) = 0.0981043 × 0.0971505 ≈ 0.0095294
However, the probability needs to be rounded to six decimal places, resulting in 0.009529.
Therefore, the correct answer is not listed among the options provided in the question, suggesting there may have been an error in the question or provided choices.