Question

If the equilibrium constant for a reaction a + b <=> 2c is measured as keq = 8.412. what would the value be for the same reaction if written as 2c <=> a + b. Kₑq' = ____. 3 sig.

Answer 1

The equilibrium constant for the reverse reaction 2c <=> a + b would be 0.119, calculated as the reciprocal of the original equilibrium constant (to three significant figures).

Step-by-step explanation:

If the equilibrium constant Keq for the reaction a + b <=> 2c is 8.412, the value of the equilibrium constant Keq' for the reverse reaction 2c <=> a + b would be 0.119 (to three significant figures).

The relationship between the forward and reverse reactions is such that Keq' = 1 / Keq. Therefore, for the given equilibrium constant of 8.412, the equilibrium constant for the reverse reaction is simply the reciprocal of this value, which calculates to 0.119 when rounded to three significant figures. This reflects the fact that equilibrium constants for reverse reactions are the inverse of those for the forward reactions.